1998–99 Unione Sportiva Ancona 1905 season - season of football team. Article “Ancona Calcio 1998-1999” in Italian Wikipedia has 6.5 points for quality (as of July 1, 2025). The article contains 0 references and 4 sections.
Since the creation of article “Ancona Calcio 1998-1999”, its content was written by 11 registered users of Italian Wikipedia and edited by 11 registered Wikipedia users in all languages.
The article is cited 248 times in Italian Wikipedia and cited 248 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Italian: #409997 10.2016 |
Global: #4926135 05.2020 |
| Best Rank | Italian: #42512 07.2019 |
Global: #923334 07.2019 |
On 16 March 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: 98th Academy Awards, Michael B. Jordan, Sinners, Jessie Buckley, Paul Thomas Anderson, Sean Penn, One Battle After Another, Amy Madigan, Hamnet, Timothée Chalamet.
In Italian Wikipedia the most popular articles on that day were: Premi Oscar 2026, Una battaglia dopo l'altra, Michael B. Jordan, I peccatori, Andrea Kimi Antonelli, Jessie Buckley, Sean Penn, Paul Thomas Anderson, Amy Madigan, Hamnet - Nel nome del figlio.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(15+0+0+17.39+0)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
